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It’s hard to beat a team three times in a season
An email from a good buddy of mine (and occasional commenter here):
i am so sick and tired of hearing "its so hard to beat a team three times in a season". idiots. yes, going 3-0 vs a playoff team is hard. BUT NOT IF YOU SPOT TEAM A TWO GAMES YOU MORONS.
He's right, of course. This is essentially the same reason why black isn't necessarily a good bet on a roulette wheel that's come up red on the last ten spins. Yes, it's incredibly unlikely for a wheel to land on red on eleven straight spins, but given that it's already landed on red for the last ten spins, it's not at all unlikely for it to land on red for the eleventh. Likewise, before the season, the Cowboys beating the Giants three times would have been something of a longshot. But now that they've already done two-thirds of the work, it's not.
Anyone making the hard-to-beat-a-team-three-times claim probably is suffering from a failure to understand conditional probability, but that doesn't necessarily make them wrong. Football games are not roulette wheels. In particular, they're not independent. Maybe teams learn more from losses than from wins, or something like that, and it really is hard to beat a team three times, even if you've already beat them twice. That's an empirical question. Let's check it out.
Since the merger, there have been 17 instances of a team trying to beat another team thrice in a season. In 11 of those cases, the team succeeded. Teams, like this year's Cowboys, who have the better record and were therefore playing at home, are 9-3 when trying to beat a team three times in a season. Here's the data:
+------+-------+-----------+-------+-----------+-----+-------+ | year | team1 | t1_record | team2 | t2_record | loc | score | +------+-------+-----------+-------+-----------+-----+-------+ | 2004 | GNB | 10-6-0 | MIN | 8-8-0 | H | 17-31 | | 2004 | STL | 8-8-0 | SEA | 9-7-0 | R | 27-20 | | 2002 | PIT | 10-5-1 | CLE | 9-7-0 | H | 36-33 | | 2000 | NYG | 12-4-0 | PHI | 11-5-0 | H | 20-10 | | 1999 | TEN | 13-3-0 | JAX | 14-2-0 | R | 33-14 | | 1998 | DAL | 10-6-0 | ARI | 9-7-0 | H | 7-20 | | 1997 | NWE | 10-6-0 | MIA | 9-7-0 | H | 17-3 | | 1997 | GNB | 13-3-0 | TAM | 10-6-0 | H | 21-7 | | 1994 | PIT | 12-4-0 | CLE | 11-5-0 | H | 29-9 | | 1994 | MIN | 10-6-0 | CHI | 9-7-0 | H | 18-35 | | 1993 | RAI | 10-6-0 | DEN | 9-7-0 | H | 42-24 | | 1992 | KAN | 10-6-0 | SDG | 11-5-0 | R | 0-17 | | 1991 | KAN | 10-6-0 | RAI | 9-7-0 | H | 10-6 | | 1989 | HOU | 9-7-0 | PIT | 9-7-0 | H | 23-26 | | 1986 | NYG | 14-2-0 | WAS | 12-4-0 | H | 17-0 | | 1983 | SEA | 9-7-0 | RAI | 12-4-0 | R | 14-30 | | 1982 | MIA | 7-2-0 | NYJ | 6-3-0 | H | 14-0 | +------+-------+-----------+-------+-----------+-----+-------+
This entry was posted on Tuesday, January 8th, 2008 at 4:44 am and is filed under General, History. You can follow any responses to this entry through the RSS 2.0 feed. Both comments and pings are currently closed.

Another split is that teams with less than 6 losses are 7-0 after winning 2.
The data is when team1 had a 2-0 record against team2, and played for the 3rd time, right? I read someplace else there were something like 50 instances of teams playing 3 times.
50+ instances yes, but that includes instances when the teams split the 1st two. So, if anyone uses those games as evidence that it is "hard to go 3-0", they are, well, read the above quote...
Another theme from last weekend in a similar vein... people kept talking about how the Steelers had never lost to the same team at home twice in one year. Does anyone know how many teams have had the chance to beat the Steelers at home twice? It can't be a large number, right?
Sorting through my database I used for yesterday's post, here are some interesting splits when it comes to playoff games between division opponents. (Since I didn't use 1982 or 1987, I don't have the Mia-Jets game listed above).
Playoff Matchups where one team had swept, or the teams had split by each winning on road in regular season: 29 games, Home team 18-11, average HFA = +0.8
Playoff Matchups where the teams had split in the regular season, with both teams winning at home in the regular season: 24 games, Home Team 16-8, average HFA = +6.2
Breaking the first category down further, and getting into really small sample sizes:
Home Team Swept: 8-4, average HFA = +2.0
Home Team was swept: 2-2, average HFA = -1.6
Teams split, road W's: 8-5, average HFA = +0.6
Eric J, I thought the exact same thing. To beat the Steelers twice at home in a season means you'll have to play them in the playoffs.
The teams that have had a chance to even play the Steelers twice in Pittsburgh in a season:
2007 Jaguars - obviously did it, even though they interestingly blew 18 and 15 pt leads in the 4th quarter before winning both games
2004 Jets - lost both games
2004 Patriots - lost in the reg. season, won the AFC-C
2002 Browns - lost all 3 meetings that year
2001 Ravens - Ravens beat them in the reg. season, but lost in the playoffs (and haven't won a playoff game since)
1997 Patriots - Pats lost both games
1997 Broncos - Lost in the reg. season but won the AFC-C
1994 Browns - Lost all 3 meetings
1979 Oilers - Lost both games
1978 Oilers - Won in the reg. season but lost the AFC-C
1972 Raiders - Lost both games
1947 Eagles - Lost the reg. season, won in the playoffs
So that's only 12 teams that ever had an opportunity to do it. And out of the 12, only 3 (07 Jags, 01 Ravens, 78 Oilers) had the first game won when they went into the playoff match-up. They were boosting it up as a great feat, but I thought it meant very little.
And I love that the last two times Cleveland made the playoffs, they were beat by Pittsburgh for the third time that season. And they can also blame not winning the division this year on blowing that 15-pt lead in Pittsburgh.
So, if I'm reading JKL's comment right, that means that there have been 53 instances since the merger of teams playing each other 3 times in a season (2x regular, 1x playoffs), discounting 1982 and 1987.
According to the original post, in 10 of those 53 instances (discounting the 1982 game), one team won all 3 of those matchups.
Given just a straight 50% chance of any team winning any game, that would mean that you'd expect a "three-peat" to occur in 1 out of every 8 instances, or about 6.6 times. In reality, it's happened 10/53 = 18.8% of the time.
The three-peating team is probably actually better than the team it's beating, though. For an 18.8% chance of a three-peat, the winning team would have to be expected to win 57.4% of the time.
This obviously doesn't take home field into account, but it hardly seems a stretch to say that one team would be better than another team 57.4% of the time, all other things being equal.
I think the basic odds are 1/4 - for evenly matched teams, 1/8 for either one of them. There may be a slight bias where 2-0 series are less likely to lead to 2 teams in the playoffs. 17/53 seems farther from 1/2 than 10/53 is from 1/4, although I seem to have mislaid my binomifocals.
Scott, I ended up going through the same exercise later and came up with 9 teams, instead of 12... I think the first game between the Pats and Steelers in '97 was at New England. I missed the '47 Eagles, though. So, the 10 teams to play at PIT twice before this year went 5-15 in those games. That's without getting into the selection biases involved - you'd only play there twice when they're good enough to have a home playoff game, for example. Plus, a win over them during the regular season would make it less likely that you'd have to play them in Pittsburgh in the playoffs.
So with Dallas losing following the 2007 season, teams going for 3-0 against a team pulled it off are 11-7. And the better record at home going for it are 9-4.
Following the 2008 season, Pittsburgh is going to try and move those records to 12-7 and 10-4.
the titans in 99 beat the jags twice in the regular season, and ruined them in the playoffs...